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Section 9.1 Parametric Representation of Surfaces

As noted in the introduction to the present chapter, a surface, S, is a deformed plane domain, DR2, lying in space. Hence to describe S mathematically we need to say which point in D corresponds to what point on S, just as a map of the world (represented by D) shows the geographic locations in the real world (the surface S). This correspondence defines a (vector valued) one-to-one function g from D to R3 whose image is S. The function g:DR3 is called a parametrisation of S. Some surfaces cannot be represented by one single parametrisation, or it is not convenient to do so. (To represent the world we often use a collection of maps, an atlas, and not a single map of the whole world.) As with parametrisations of a curve, a parametrisation of a surface is never unique! We call a representation by means of a parametrisation a parametric representation of a surface.
The above class of surfaces is too big. We only want to work with smooth (or at least piecewise smooth) surfaces. To define exactly what we mean by a smooth surface let us assume that g:DR3 is the parametrisation of (part of) a surface. Suppose that a=(a1,a2)D, so that g(a) is the corresponding point on S. Then the map
x1g(x1,a2)
is the parametrisation of a curve on S through g(a). Similarly, the map
x2g(a1,x2)
is the parametrisation of another curve on S through g(a). In order for S to be smooth we assume that these curves are smooth. More precisely this means that the above are regular parametrisations, so in particular we require that
vi:=xig(a)0
for i=1,2. For S to be smooth we require more. If we are very unlucky, the image of D is only a curve, and not a surface. In that case the vectors v1 and v2 are parallel. To prevent this we require in addition to the above that v1 and v2 not be parallel. Both of the above requirements are satisfied if and only if the area of the parallelogram spanned by v1 and v2 is nonzero. In Theorem 1.16 we derived a formula to compute the area of a parallelogram. We have to form the matrix with columns v1 and v2, which in our present case is the Jacobian matrix Jg(a) of g at a. According to Theorem 1.16 the surface area spanned by v1 and v2 is
det((Jg(y))TJg(y)).
Because of its significance in the theory of surfaces, or more generally in differential geometry, the the square root has a name.

Definition 9.1. Jacobian of a parametrisation.

Suppose that g:RkRN is a differentiable map. Then the expression
det((Jg(y))TJg(y))
is called the Jacobian of the parametrisation g at y.

Definition 9.2. Regular parametrisation.

Suppose that g:DR3 is the parametrisation of (part of) a surface. We say that g is a regular parametrisation of (part of) S, if the Jacobian of g is nowhere zero. Finally, S is called a smooth surface, if it can be fully described by one (or several) regular parametrisation. If several parametrisations are required then their images on S must not overlap by more than just a line.
We also sometimes look at piecewise smooth surfaces which are finite unions of smooth surfaces.

Example 9.3. Jacobian of a sphere.

Suppose that S is the sphere of radius R centred at the origin in R3. We can describe every point on that sphere by indicating two angles, one from the vertical, the other from the horizontal. (Called latitude and longitude on a map of the world). According to the considerations in Subsection 6.4.1 a parametrisation is given by
g(θ,φ):=(Rcosφsinθ,Rsinφsinθ,Rcosθ),
where (θ,φ)D:=[0,π]×[0,2π). This is the same as Subsection 6.4.1, except that we keep the radius constant. We next show that g is a regular parametrisation. To do so we compute the Jacobian matrix
Jg(θ,φ)=R[cosφcosθsinφsinθsinφcosθcosφsinθsinθ0].
Now we compute the product
(Jg)TJg=R2[cosφcosθsinφcosθsinθsinφsinθcosφsinθ0][cosφcosθsinφsinθsinφcosθcosφsinθsinθ0]=R2[100sin2θ]
and thus
det((Jg)TJg)=R4det[100sin2θ]=R4sin2θ.
As sinθ0 for (θ,φ)(0,π)×[0,2π), the Jacobian is nonzero except for the points at the point on top and the bottom of the sphere (θ=0,π). For most purposes these exceptional points are irrelevant.

Remark 9.4.

It is the subject of differential geometry to study k-dimensional surfaces in RN (k=1,,N). Our definition of regular parametrisation can be generalised to this context. In particular, if k=1, it is consistent with the notion of regular parametrisation of curves given in Definition 7.2. Indeed, if γ(t), tI, is the parametrisation of a curve, C, then the Jacobian matrix of γ(t) is
Jγγ(t)=γ(t)=[γ1(t)γN(t),]
and we get
(Jγγ(t))TJγγ(t)=γ(t)Tγ(t)=γ(t)2.
We said that γ(t), tI, is a regular parametrisation if γ(t)0 for all tI, showing that the two definitions are consistent.